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A body is moving with uniform velocity of `8 ms^-1`. When the body just crossed another body, the second one starts and moves with uniform acceleration of `4 ms^-2`. The time after which two bodies meet will be :A. `2s`B. `4 s`C. `6 s`D. `8 s` |
Answer» Correct Answer - B b. Let they meet after time `t`, then the diatance travelled by both in time `t` should be same `s=8t=(1)/(2) 4t^(2) rArr t =4 s`. |
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