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A body is moving with velocity `30 m//s` towards east. After `10 s` its velocity becomes `40 m//s` towards north. The average acceleration of the body is.A. ` 1 m//s^2`B. ` 7 m//s^2`C. ` sqrt 7 m//s^2`D. `5 m//s^@` |
Answer» Correct Answer - B Velocity towaeds East,` vec v_1 = 30 hat I m//s` Velocity towaeds Noth, ` vec v_2 = 40 hat j m//s` Change in velocity, ` Delta vec v= vec r- vec v-1 = ( 40 hat j - 30 hat i)` ` |Delta vec v|= | 40 hat j - 30 aht i| = sqrt ( 40^2 + (- 30)^2) = 50 m//s` Average acceleration , ` a_(av) = (| Delta vec v|/(Deltat) = ( 50 m//s)/( 10 s) = 5 m//s^2`. |
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