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A body is oscillating vertical about its mean position with period `sqrt(3)` s. If its maximum and minimum heights above the surface of the ground are 2 m and 1.5 m, then the speed at midway between mean and extreme position will beA. `5 m//s`B. `(pi)/(4) m//s`C. `10 m//s`D. `(pi)/(sqrt(3)) m//s` |
Answer» Correct Answer - B `2A=2-1.5 therefore A=(0.5)/(2)=0.25m` `v=omegasqrt(A^(2)-x^(2))therefore x=A//2` `v=(sqrt(3))/(2)Aomega=(sqrt(3))/(2)xx(1)/(4)xx(2pi)/(sqrt(3))` `=0.866 A omega` |
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