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A body is projected at an angle of 60^° with horizontal with a speed of 40m/s The speed of the body when velocity becomes perpendicular to initial velocity is(g=10m/s² 1.20\surd3m/s 2.40/\surd3m/s 3.20m/s 4.30m/

Answer» A body is projected at an angle of 60^° with horizontal with a speed of 40m/s The speed of the body when velocity becomes perpendicular to initial velocity is(g=10m/s² 1.20\surd3m/s 2.40/\surd3m/s 3.20m/s 4.30m/


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