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A body is projected up from the bottom as inclined plane with velocity `3sqrt3m//sec` which makes an angle `60^(@)` if the horizontal. The angle of projection is `30^(@)` with the plane then the time of flight when it strikes the same plane is `0.1x.`Then the value of `x` is |
Answer» `T=(2V_(0)sin(theta-alpha))/(g cos alpha)=(2xx3sqrt(3) sin (60-30))/(10 cos 30)` `=(2xx3sqrt3xx1/2)/(10xxsqrt3/2)=0.6=0.1x , x=6` |
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