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A body is projected up such that its position vector varies with time as `vecr={3thati+(4t-5t^(2))hatj} m`. Here `t` is in second.The time when its `y`-coordinate is zero isA. `3 s`B. `1 s`C. `0.8 s`D. `1.25 s` |
Answer» Correct Answer - C `4t-5t^(2)=0` |
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