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A body is projected vertically up from the ground crosses point \( A , B \) and \( C \) with velocities \( 3 V , 2 V \) and \( V \) respectiyely. Then \( AB : BC = \)A) \( 3: 1 \)B) \( 5: 3 \)C) \( 2: 1 \)D) \( 3: 5 \) |
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Answer» Velocity of A = 3v Velocity of B = 2v Velocity of C = 1v Then \(AB:BC\) \(= 3 \times 2:2\times 1\) \(= 6:2\) \(= 3:1\) |
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