A body is projected vertically up. What is the distance covered in its last second of upward motion? (g=10 m//s^(2))

A body is projected vertically up. What is the distance covered in its

1.	A body is projected vertically up. What is the distance covered in its last second of upward motion? (g=10 m//s^(2))
Answer» `19.6ms^(-1)` `58.8ms^(-1)` `49ms^(-1)` `65ms^(-1)` SOLUTION :