A body is projected vertically up with velocity u from a tower. It reaches the ground with velocity nu. The height of the tower is H=u^(2)/(2g) (n^(2)-1).

A body is projected vertically up with velocity u from a tower. It rea

1.	A body is projected vertically up with velocity u from a tower. It reaches the ground with velocity nu. The height of the tower is H=u^(2)/(2g) (n^(2)-1).
Answer» Solution :`V^(2)-U^(2)=2as, "Here u=u, v=NU, a=-g, s=-H"` `(nu)^(2)-u^(2)=2gH ` `(n^(2)-1)u^(2)=2gH ""H=(u^(2))/(2g) (n^(2)-1)`