A body is projected vertically up with velocity u from a tower. It reaches the ground with velocity nu. The height of the tower is H=(u^(2))/(2g)(n^(2)-1)

A body is projected vertically up with velocity u from a tower. It rea

1.	A body is projected vertically up with velocity u from a tower. It reaches the ground with velocity nu. The height of the tower is H=(u^(2))/(2g)(n^(2)-1)
Answer» Solution :`v^(2)-u^(2)=2AS` Here `u=u,v=n u,a=-g,s=-H` `(n u)^(2)-u^(2)=2gH, (n^(2)-1)u^(2)=2gH` `THEREFORE H=(u^(2))/(2G)(n^(2)-1)`