1.

A body is projected vertically upward with the velocity v=3hati+4hatjms^(-1). The maximum height attained by the body is (g=10ms^(-2)).

Answer»

7m
1.25m
8m
0.08m

Solution :`V=3hati+4hatj`
`H_(max)=(v^(2)sin^(2)theta)/(2G)=(v^(2))/(2g)""[:.thet=90^(@)]`
`v=sqrt(9+16)=sqrt25`
`:.v^(2)=25""H_(max)=(25)/(20)=(5)/(4)=1.25m`


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