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A body is projected vertically upwards from the surface of a planet of radius R with a velocity equal to 1/3rd the escape velocity for the planet. The maximum height attained by the body is |
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Answer» `R//2` `v^(2)=u^(2)+2gh` when `u=0rArrv=sqrt(2gh)` Given, `v=(v_(e))/(3)`, where, `v_(e)=sqrt(2gR)rArr sqrt(2gh)=(1)/(3)sqrt(2gR)` On squaring both sides of equation, we get `h=(R)/(9)` |
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