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A body is projected with a speed v0 horizontally from the top of a tower. Find the horizontal displacement of the particle, when the magnitude of vertical component of velocity is equal to magnitude of horizontal component of velocity.Options: |
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Answer» Horizontal displacement =v0t [as the acceleration is zero] In a horizontal projectile, horizontal velocity remains constant. it is given that at a certain time horizontal velocity is equal to vertical velocity vy = v0 Generally, vy = u + gt [u = 0] v0 = gt t = v0 /g ----------(1) As given above horizontal displacement at time t = v0t ----------(2) substitute the above equation (1) in (2) sx = v0 (v0 /g) sx = v0 2 /g
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