A body is projected with a velocity u so that the horizontal range is twice the maximum height. Then the maximum height is

A body is projected with a velocity u so that the horizontal range is

1.	A body is projected with a velocity u so that the horizontal range is twice the maximum height. Then the maximum height is
Answer» `(U^(2))/(2G)` `(u^(2))/(G)` `(5u^(2))/(4G)` `(2u^(2))/(5g)` Answer :D