A body is projected with a velocity v at an angle of projection θ with the horizontal. The direction of velocity of the body makes angle 30∘ with the horizontal at t=2 s and then after further 1 s, it reaches the maximum height. Then (g=10 m/s2)

A body is projected with a velocity v at an angle of projection θ wit

1.	A body is projected with a velocity v at an angle of projection θ with the horizontal. The direction of velocity of the body makes angle 30∘ with the horizontal at t=2 s and then after further 1 s, it reaches the maximum height. Then (g=10 m/s2)
Answer» A body is projected with a velocity $v$ at an angle of projection $θ$ with the horizontal. The direction of velocity of the body makes angle $30^{\circ}$ with the horizontal at $t = 2 s$ and then after further $1 s$ , it reaches the maximum height. Then $(g = 10 {m/s}^{2})$

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A body is projected with a velocity v at an angle of projection θ with the horizontal. The direction of velocity of the body makes angle 30∘ with the horizontal at t=2 s and then after further 1 s, it reaches the maximum height. Then (g=10 m/s2)

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