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A body is released from the top of a smooth inclined plane of inclination theta. It reaches the bottom with velocity v. If the angle of inclination is doubled for the same length of the plane, what will be the velocity of the body on reaching the ground |
Answer» <html><body><p>v<br/>2v<br/>`(2cos theta)^((1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))v`<br/>`(2 <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> theta)^((1)/(2))v`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`v=sqrt(2gl sin theta), v^(1)=sqrt(2gl sin 2 theta)`</body></html> | |