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A body is released from the top of a smooth inclined plane of inclination `theta`. It reaches the bottom with velocity `v`. If the angle of inclina-tion is doubled for the same length of the plane, what will be the velocity of the body on reach ing the ground .A. `v`B. `2v`C. `(2 cos theta)^(1/2) v`D. `(2 cos theta)^(1/2) v` |
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Answer» Correct Answer - C `v =sqrt(2glsin theta),v^(1)=sqrt(2glsin2theta)` `F_(UP) = mg (sin theta +mu_(k) cos theta)` . |
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