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A body is suspended at the end of a spring hanging vertically and it oscillates with a time period of 1.414 s. The spring is then cut into two equal parts and the same body attached to one of the pieces is made to oscillate. What will be the time period of oscillation ? |
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Answer» Solution :For the orignal SPRING `T= 2pi SQRT(m/k)` , where T = 1.414 s or `SQRT2` s. If the spring is cut into two equal parts spring constant of each will be 2K. Then `T^1 = 2pi sqrt(m/k) , 1/(sqrt2) T= 1s` |
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