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A body is thrown on a rough surface such that the friction force acting on it is linearly varying with the distance travelled by it as `f=ax+b`. Find the work done by the friction on the box if before coming to rest the box travels a distance s. |
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Answer» As the force is acting in the direction opposite to the motion of the box, work done by this force must be negative. As force is not constant, we use `W=-underset0oversetsintintfdx=-underset0oversets int(ax+b)*dx=((ax^2)/(2)+bx)_0^s` `=-1/2as^2-bs` |
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