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A body mass `2kg` has an initial velocity of 3 metre//sec along OE and it is subject to a force of `4N` in a direction perpendicular to OE. The distance of body from `O` after 4 sec will be: A. 12 metresB. 20 metresC. 8 metresD. 48 metres |
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Answer» Correct Answer - B The acceleration of the body perpendicular to `OE` is `a=(F)/(m)=(4)/(2)=2m//s^(2)` Displacement along `OE` , `s_(1)=vt=3xx4=12m` Displacement perpendicular to `OE` `s_(2)=(1)/(2)at^(2)=(1)/(2)xx2xx(4)^(2)=16m` the resultant displacement `s=sqrt(s_(1)^(2)+s_(2)^(2))=sqrt(144+256)=sqrt(400)=20m` |
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