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A body moving along a straight line is brought to rest in `2 sec` by a force `F_(1)` and in `3 sec`. By a force `F_(2)` the ratio `F_(1)//F_(2)` isA. `2:3`B. `1:1`C. `3:2`D. `9:4` |
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Answer» Correct Answer - C As force `=("change in momentum")/("time taken") :. (F_(1))/(F_(2))=(t_(2))/(t_(1))=3/2`. |
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