1.

A body moving along a straight path covers one-third of a distace with a velocity of 5 Kmph and the rest of the path with a velocity of 20 Kmph. Find the average velocity of the body

Answer»

Solution :Let the length of the PATH be 'x' the time taken by the body to reacyh (1/3) RD of he distance be `'t_(1)'` and the time taken by body to cover REST of the distancebe `'y_(2)'`
5Kpmph `=((x//3))/(t_(1)) , 20 Kmph =((2x//3))/(t_(2))`
`rArr t_(1)=(x)/(15)` hours, `t_(2)=(x)/(30)` hours
Average velocity = `("TOTAL displacement")/("Total time taken") =(x)/(t_(1)+t_(2))=10Kmph`


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