A body moving with a speed of 54kmph is brought to rest in a distances. If the coefficient of friction between the body and the surface is 0.3. Calculate the distance travelled by the body ?

A body moving with a speed of 54kmph is brought to rest in a distances

1.	A body moving with a speed of 54kmph is brought to rest in a distances. If the coefficient of friction between the body and the surface is 0.3. Calculate the distance travelled by the body ?
Answer» Solution :`u=54` KMPH `=15m//s`, `s=?`, `mu_(k)=0.3` FINAL velocity `=0` The KINETIC energy of the BODY is used to do work against friction. `(1)/(2)"MU"^(2)=mu_(k)` mgs , `s=(u^(2))/(2mu_(k)g)=(15xx15)/(2xx0.3xx9.8)=38.3m`