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A body moving with uniform acceleration along a straight line covers 60m in the 5th second and 80m in the 8th second of its motion. Calculate the initial velocity and uniform acceleration. |
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Answer» The distance travelled during the nth second is given by, sn = u + a/2(2n – 1), n = 5 and sn = 60 ∴ 60 = u + a/2 (2 × 5 – 1) 60 = u + 9a/2 ………… (1) Similarly, for n = 8, sn = 80 ∴ 80 = u + a/2 (2 × 8 – 1) 80 = u + 15a/2 …………….. (2) (2) – (1), gives 20 = 6a/2 = 3a ∴ a = 20/3 ms-2 Using this in equation (1), we get 60 = u + (9 x 20)/(2 x 3) u = 60 – 30 = 30 ms-1 |
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