A body of 0.5 kg thrown upwards reaches a maximum height of 5 m. Calcu

1.	A body of 0.5 kg thrown upwards reaches a maximum height of 5 m. Calculate the work done by the force of gravity during this vertical displacement.
Answer» Given: Mass (m) = 0.5 kg Acceleration due to gravity (g) = -9.8 m/s² Displacement (s) = 5 m. To Find: Work done (W) = ? Formula: W = P.E = mgh Solution: W = mgh = 0.5 x (-9.8) x 5 = -24.5 J The work done by the force of gravity is -24.5 joule.

A body of 0.5 kg thrown upwards reaches a maximum height of 5 m. Calculate the work done by the force of gravity during this vertical displacement.

Answer»

Given:

Mass (m) = 0.5 kg

Acceleration due to gravity (g) = -9.8 m/s²

Displacement (s) = 5 m.

To Find:

Work done (W) = ?

Formula:

W = P.E = mgh

Solution:

W = mgh

= 0.5 x (-9.8) x 5

= -24.5 J

The work done by the force of gravity is -24.5 joule.