A body of mass 0.3 kg is tken up an inclined plane of length to m and height 5 m and then allowed to slide down to bottom again. Find kinetic energy at the end of the trip.

A body of mass 0.3 kg is tken up an inclined plane of length to m and

1.	A body of mass 0.3 kg is tken up an inclined plane of length to m and height 5 m and then allowed to slide down to bottom again. Find kinetic energy at the end of the trip.
Answer» SOLUTION : `sintheta=(5)/(10)=(1)/(2)=SIN.(pi)/(6)` so, `theta=(pi)/(6)` P.E at top = `0.3xx9.8xx5=14.7J` `{:("K.E at the END"),("of TRIP"):}}={{:("P.E at top"),("- Work done"),("against friction"):}` `K.E=14.7-7.6` `=7.1J`