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A body of mass 0.40 kg moving initially with a constant speed of 10 m s^(-1) to the north is subject to a constant force of 8.0 N directed towards the south for 30 s.Take the instant the force is applied to bet = 0, the position of the body at that time to be x = 0, and predict its position att = –5 s, 25 s, 100 s.

Answer» <html><body><p></p>Solution :u = `<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> ms^(-1)` <br/> m= 0.40kg (Northdirection) <br/>t=30 s <br/> Herenorthdirectionis consideredas <a href="https://interviewquestions.tuteehub.com/tag/positiveand-2943357" style="font-weight:bold;" target="_blank" title="Click to know more about POSITIVEAND">POSITIVEAND</a> southdirectionisconsideredas negative<br/>Forceis appliedfor t=30 s <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C05_E02_022_S01.png" width="80%"/> <br/> (i) At t=5 sposition <br/> `X_(1) = ut` <br/>`=10xx (-5)` <br/> (ii)at t=25 s <br/> `x_(2)ut + (1)/(2)4r^(2)` <br/> where`a = (F )/( m ) =(-8)/(0.4)= - 20ms^(-2)` <br/> `=<a href="https://interviewquestions.tuteehub.com/tag/250-297421" style="font-weight:bold;" target="_blank" title="Click to know more about 250">250</a>- 6250` <br/> `-=6 km` <br/>when forceis appliedfor 30s distancecovered<br/> velocityof objectafter30 s <br/> = u+ 9t <br/>=10 -600 <br/> (<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>)Positionof objectat t=100s <br/> `:.x_(100)= x_(30) a + x_(70)` <br/>=-870041300 <br/> `=-5000 m` <br/> `=-50 km` <br/> Thuspositionat -5 s 25 s and 10 willbe-50 m-6 kmand-50 km</body></html>


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