A body of mass 0.5 kg travels in a straight line with velocity v = kx^(3//2) where k = 5 m^(-1//2) s^(-1) What is the work done by the net force during its displacement from x = 0 to x = 2 m?

A body of mass 0.5 kg travels in a straight line with velocity v = kx^

1.	A body of mass 0.5 kg travels in a straight line with velocity v = kx^(3//2) where k = 5 m^(-1//2) s^(-1) What is the work done by the net force during its displacement from x = 0 to x = 2 m?
Answer» 25 J 50 J 100 J 150J Solution :Given : `v = kx^(3//2)` ACCELERATION, `a = (dv)/(dt) = (dv)/(DX)(dx)/(dt) = v (dv)/(dx)` As `v^2 = k^2 x^3 :. 2v (dv)/(dx) = 3k^2 x^2 :. a = 3/2 k^2 x^2` Force, `F = ma = 3/2 mk^2 [(x^3)/(3)]_(0)^(2) = 3/2 xx 0.5 xx 5^2 xx 8/3 = 50 J`