A body of mass 1.0 kg is rotating on a circular path of diameter 2.0 m at the rate of 10 rotations in 31.4 s. The angular momentum of the body, in kg m^2/s, is

A body of mass 1.0 kg is rotating on a circular path of diameter 2.0 m

1.	A body of mass 1.0 kg is rotating on a circular path of diameter 2.0 m at the rate of 10 rotations in 31.4 s. The angular momentum of the body, in kg m^2/s, is
Answer» `1.0` `1.5` `2.0` `4.0` SOLUTION :Here , Mass M = 1.0 kg , Diameter , D = 2.0 m `therefore` Radius `R = (D)/(2) = 1.0` m The moment of inertia of the body is `I = MR^(2) = (1.0 Kg) (1.0 m)^(2) = 1.0 kg m^(2)` The ANGULAR velocity of the body is `omega = 2 pi epsilon = 2 xx 3.14 xx (10)/(31.4)` = rad/s = 2 rad/s The angular momentum of the body is `L = I omega = (1.0 kg m^(2))` (2 rad/s) = 2 kg `m^(2)//s`