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A body of mass 1 kg accelerates uniformly from rest to a velocity of 1 m s^(-1) in 15 seconds. At what time the kinetic energy of the body will be 2/9 J ? |
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Answer» Solution :`a = (1 - 0)/(15) ms^(-2) = 1/15 ms^(-2)` ALSO, `1/2 xx 1 xx v^2 = 2/9 or v = 2/3 ms^(-1)` Now, `2/3 = 0 + 1/15 xx t " or " t = 10 s` |
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