A body of mass 10 kg is placed on rough surface, pulled by force F making an angle of 30^(@) above the horizontal. If the angle of friction is also 30^(@), then the minimum magnitude of force F required to move the body is equal to( take, g=10 ms^(-2))

A body of mass 10 kg is placed on rough surface, pulled by force F mak

1.	A body of mass 10 kg is placed on rough surface, pulled by force F making an angle of 30^(@) above the horizontal. If the angle of friction is also 30^(@), then the minimum magnitude of force F required to move the body is equal to( take, g=10 ms^(-2))
Answer» 100 N `50 sqrt(2)N` `100sqrt(2)N` 50N Solution :(d) `mu= tan 30^(@)=(1)/(sqrt(3))(30^(@)`=angle of FRICTION) `N=mg-F-sin 30^(@)=(100-(F)/(2))` ` implies"" (sqrt(3)F)/(2)=(1)/(sqrt(3))(100-(F)/(2))` ` implies (3F)/(2) =100-(F)/(2) implies F=50N`