1.

A body of mass 10 kg moving at a height of 2 m, with uniform speed of 2 m/s. Its total energy is

Answer» Kinetic energy= 1/2mv^2= 1/2*10*2*2=20joulePotential energy=mgh= 10*9.8*2= 196 jouleTotal energy= 196+20=216 joule<br>Kinetic energy = 1/2 mv^2 = 10 × (2) ^2 /2 = 200 J. // Potential energy = mgh = 10 × 9.8 × 2 = 196 J. Therefore, total energy = 200 + 196 = 396 J. //


Discussion

No Comment Found