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A body of mass `10 mg` is moving with a velocity of `100 ms^(-1)`. The wavelength of the de Broglie wave associated with it would beA. `6.63 xx 10^(-31)m`B. `6.63 xx10^(-35)m`C. `6.63 xx10^(-34) m`D. `6.63 xx10^(-7) m` |
Answer» Correct Answer - A The de Broglie equation allows the calculation of wavelength of any perticle or object of mass `m` moving at velocity `v`: `lambda = (h)/(mv)` `=((6.63xx10^(-34)kgm^(2)s^(-1)))/((10xx10^(-6)kg)(100ms^(-1)))` `= 6.63 xx 10^(-31)m` Note that `1mg = 10^(-3)g` and `1g = 10^(-3)kg`. Thus, `1mg = 10^(-6)kg` |
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