A body of mass 100 grams is tied to one end of a string and revolved a

1.	A body of mass 100 grams is tied to one end of a string and revolved along a circular path in the horizontal plane. The radius of the circle is 50 cm. If the body revolves with a constant angular speed of 20 rad/s, find the1. period of revolution 2. linear speed 3. centripetal acceleration of the body.
Answer» Data : m = 100 g = 0.1 kg, r = 50 cm = 0.5 m, ω = 20 rad/s 1. The period of revolution of the body, T = \(\frac{2\pi}{\omega}\) = \(\frac{2\times 3.142}{20}\) = 0.3142 s 2. Linear speed, v = ωr = 20 × 0.5 = 10 m/s 3. Centripetal acceleration, a_c = w²r = (20)² × 0.5 = 200 m/s²

A body of mass 100 grams is tied to one end of a string and revolved along a circular path in the horizontal plane. The radius of the circle is 50 cm. If the body revolves with a constant angular speed of 20 rad/s, find the1. period of revolution 2. linear speed 3. centripetal acceleration of the body.

Answer»

Data : m = 100 g = 0.1 kg, r = 50 cm = 0.5 m, ω = 20 rad/s

1. The period of revolution of the body,

T = \(\frac{2\pi}{\omega}\) = \(\frac{2\times 3.142}{20}\) = 0.3142 s

2. Linear speed, v = ωr = 20 × 0.5 = 10 m/s

3. Centripetal acceleration,

a_c = w²r = (20)² × 0.5 = 200 m/s²

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