1.

Certain stars are believed to be rotating at about 1 rot/s. If such a star has a diameter of 40 km, what is the linear speed of a point on the equator of the star?

Answer»

Data : d = 40 km, /= 1 rot/s

∴ r = \(\frac{d}2\) = \(\frac{40\,km}2\) = 20 km = 2 × 104 m

Linear speed, v = ωr = (2πf)r 

= (2 × 3.142 × 1)(2 × 104

= 6.284 × 2 × 104

= 1.257 × 105 m/s (or 125.6 km/s)



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