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A body of mass `1kg` is suspended from a weightless spring having force constant `600N//m`. Another body of mass `0.5 kg` moving vertically upward hits the suspended body with a velocity of `3.0m//s` and get embedded in it. Find the frequency of oscillations and amplitude of motion.A. `(pi)/(10)Hz`B. `(10)/(pi)Hz`C. `(1)/(2pi)Hz`D. 3.142 Hz

Answer» Correct Answer - B
`n=(1)/(2pi)sqrt((k)/(m))`
`=(1)/(2pi)sqrt((600)/(1.5))=(1)/(2pi)xx20=(10)/(pi)Hz`


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