InterviewSolution
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InterviewSolution
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A body of mass `2 kg` has an initial velocity of `3 m s^-1` along `OE` and it is subjected to a force of `4 N` in `O F` direction perpendicular to `O E`. Find the distance of the body from `O` after `4 s`. .A. `12m`B. `28m`C. `20m`D. `48m` |
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Answer» Correct Answer - c `u_(x)=3ms^(-1), as=0, u_(y)=2m//se^(2) and t=4sec`. If `s_(x) and s_(y)` be the displacement alont x-axis and y-axis respectively then `s_(x)=u_(x)t+1/2a_(x)t^(2)` `=3xx4+1/2xx0xx(4)^(2)=12m` and `s_(y)=u_(y)t+1/2a_(y)t^(2)` `=0xx4+1/2xx2xx(4)^(2)=16m` `s=sqrt(s_(x)^(2)+s_(y)^(2))=sqrt((12)^(2)+(16)^(2))` `=sqrt(144+256)=sqrt(400)=20m` |
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