A stone tied to the a string of `80 cm` long is whirled in a horizontal circle with a constant speed. If the stone makes `25` revolutions in `14 s` then, magnitude of acceleration of the same will be:A. `650 cm//s^(2)`B. `680 cm//s^(2)`C. `750 cm//s^(2)`D. `990 cm//s^(2)`

A stone tied to the a string of `80 cm` long is whirled in a horizonta

1.	A stone tied to the a string of `80 cm` long is whirled in a horizontal circle with a constant speed. If the stone makes `25` revolutions in `14 s` then, magnitude of acceleration of the same will be:A. `650 cm//s^(2)`B. `680 cm//s^(2)`C. `750 cm//s^(2)`D. `990 cm//s^(2)`
Answer» Correct Answer - d If angular velocity is `omega` and radius of circular path is r then, acceleration `alpha=omega^(2)r` `T=("Number of revolution")/("Time taken")=25/14=1.78s` and `omega=(2pi)/1.78=3.52 rad//s` Hence, `alpha=(3.52)^(2)xx80=991.23~~990cm//s^(2)`

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A stone tied to the a string of `80 cm` long is whirled in a horizontal circle with a constant speed. If the stone makes `25` revolutions in `14 s` then, magnitude of acceleration of the same will be:A. `650 cm//s^(2)`B. `680 cm//s^(2)`C. `750 cm//s^(2)`D. `990 cm//s^(2)`

A stone tied to the a string of `80 cm` long is whirled in a horizontal circle with a constant speed. If the stone makes `25` revolutions in `14 s` then, magnitude of acceleration of the same will be:A. `650 cm//s^(2)`B. `680 cm//s^(2)`C. `750 cm//s^(2)`D. `990 cm//s^(2)`

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