A body of mass 2 kg has an initial velocity vi=(^i+^j)ms−1. After the collision with another body its velocity becomes vf=(5^i+6^j−^k)ms−1. If the impact time is 0.02 s, the average force of impact on the body (in newton) is

A body of mass 2 kg has an initial velocity vi=(^i+^j)ms−1. After th

1.	A body of mass 2 kg has an initial velocity vi=(^i+^j)ms−1. After the collision with another body its velocity becomes vf=(5^i+6^j−^k)ms−1. If the impact time is 0.02 s, the average force of impact on the body (in newton) is
Answer» A body of mass 2 kg has an initial velocity $v_{i} = (^i +^j) m s^{- 1}$ . After the collision with another body its velocity becomes $v_{f} = (5^i + 6^j -^k) m s^{- 1}$ . If the impact time is 0.02 s, the average force of impact on the body (in newton) is

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A body of mass 2 kg has an initial velocity vi=(^i+^j)ms−1. After the collision with another body its velocity becomes vf=(5^i+6^j−^k)ms−1. If the impact time is 0.02 s, the average force of impact on the body (in newton) is

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