1.

A body of mass 2 kg is moving with a velocity of vecu= 3hati +4hatj m// s. A steady force vecF=hati-2hatj N begins to act on it. After four seconds,the body will be moving along.

Answer»

X-axis with a VELOCITY of `2 m//s`
Y-axis with a velocity of `5 m//s`
X-axis with a velocity of `5 m//s`
Y-axis with a velocity of `2 m//s`

SOLUTION :`v=u+at, F =ma`


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