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A body of mass 2 kg is placed on a horizontal frictionless surface . It is connected to one end of the a spring whose force constant is 250 N/m the other end of the spring is joining with the wall A particle fo mass 0.15 kg moving horizontally with speed V sticks to the body after collision if it compressess the spring by 10 cm the velocity of the pariticle is - A. 3 m/sB. 5 m/sC. 10 m/sD. 15 m/s |
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Answer» Correct Answer - D BY the conservation of momentum `mxxv=(m+M)V` by the conservation of enrgy `(1)/(2)kx^(2)=(1)/(2)(m+M)V^(2)` ` =(1)/(2)(m+M)((mv)/(m+M))^(2)` ` implies v= sqrt((kx^(2)(m+M))/(m^(2)))` `=(x)/(m)sqrt(k(m+M))` So v= 15 m/s |
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