A body of mass 2 kg is projected vertically up with a velocity of 100 ms^(-1) . If it rises to a height of 400 m, the energy utilized to overcome friction is (g=10ms^(-2))

A body of mass 2 kg is projected vertically up with a velocity of 100

1.	A body of mass 2 kg is projected vertically up with a velocity of 100 ms^(-1) . If it rises to a height of 400 m, the energy utilized to overcome friction is (g=10ms^(-2))
Answer» 10 KJ 8 KJ 1 KJ 2 KJ Answer :D