A body of mass 2 kg is projected vertically up with a velocity of 100 ms^(-1). If it rises to a height of 400 m, the energy utilized to overcome friction is (g = 10 ms^(-2))

A body of mass 2 kg is projected vertically up with a velocity of 100

1.	A body of mass 2 kg is projected vertically up with a velocity of 100 ms^(-1). If it rises to a height of 400 m, the energy utilized to overcome friction is (g = 10 ms^(-2))
Answer» 10 KJ 8 Kj 1 Kj 2 Kj ANSWER :D