A body of mass 2 kg travels according to the law x (t) = pt + qt^(2) + rt^(3) where, q = 4m s^(-2) , p - 3m s^(-1) and r = 5m s^(-3). The force acting on the body at t = 2s is

A body of mass 2 kg travels according to the law x (t) = pt + qt^(2) +

1.	A body of mass 2 kg travels according to the law x (t) = pt + qt^(2) + rt^(3) where, q = 4m s^(-2) , p - 3m s^(-1) and r = 5m s^(-3). The force acting on the body at t = 2s is
Answer» 136 n 134 n 158 n 68 n Solution :135 B N m=2kg Q= 4 `m//s^(2) , p-3 m//s ,r = 5 ms^(3)` `3t+ 4t^(2) + 5T^(3)` `a= (dx )/(DT )= 3(1) +(2t)+ 5(3t^(2))` at t =2 a= 8 +30(2) ForceF = ma `= 2xx 68` `136 N`