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A body of mass 2kg has an initial speed 5 m/s. A force acts as it for some time in the direction of motion. The force - time graph is shown in figure. Find the final speed of the body. |
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Answer» SOLUTION :Area of OAF `= (1)/(2)xx2xx4=4` Area of BGHC `= (1)/(2)(4+2.5)xx0.5=1.625` Area of ABGF `= 2xx4=8` Area of CDEH `= 2xx2.5=5` Total area = Change in mementum = 18.625. `m(v-u)=18.625 V =(18.625)/(2)+5` `V=14.25 m//s` |
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