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A body of mass `2kg` moving on a horizontal surface with an initial velocity of `4 ms^(-1)` comes to rest after `2` second. If one wants to keep this body moving on the same surface with a velocity of `4 ms^(-1)` the force required isA. zeroB. 2 NC. 4 ND. 8 N |
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Answer» Correct Answer - C `0=4-axx2rArra=2m//s^(2)` `F=ma=2xx2=4N` |
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