InterviewSolution
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InterviewSolution
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A body of mass `2kg` travels according to the law `x (t) = pt + qt^(2) + rt^(3)` where `p = 3ms^(-1),q = 4 ms^(-2)` and `r = 5ms^(-3)` . Find the force acting on the body at t=2 sec.A. 136 NB. 134 NC. 158 ND. 68 N |
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Answer» Correct Answer - A Given, mass `=2` kg `x(t)=pt=pt+qt^(2)+rt^(3)` `v=(dx)/(dt)=p+2qt+3rt^(2)` `a=(dv)/(dt)=0+2q+6 rt` At `t=2 s, a=2q+6xx2xxr=2q+12 r` `=2xx4+12xx5=8+60=68 ms^(-1)` Force, `F=ma=2 xx68=136 N` |
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