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A body of mass `2kg` travels according to the law `x (t) = pt + qt^(2) + rt^(3)` where `p = 3ms^(-1),q = 4 ms^(-2)` and `r = 5ms^(-3)` . Find the force acting on the body at t=2 sec.A. `136N`B. `134N`C. `158N`D. `68 N` |
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Answer» Correct Answer - A Given mass `=2kg` `x (t) =pt + qt^(2) + rt^(3)` `v =(dx)/(dt) = p + 2qt + 3rt^(2)` `a = (dv)/(dt) = 0 + 2q +6rt` ltbr gtat `t =2s, a =2q + 6 xx 2 xx r` `= 2q +12r` `= 2 xx 4 + 12 xx 5` `= 8 + 60 =68 m//s` Force ` =F =ma` `=2 xx 68 =136 N` . |
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