1.

A body of mass 3 kg is under a force causes a displacement in it, given by S=t^(2)/3 (in metres). The work done by the force in 2 s is

Answer»

2J 
3.8J
5.2J
2.6 J 

Solution :`W = int_(t = 0)^(t = 2) F dS = int_(t = 0)^(t = 2)M ((d^2S)/(dt^2))((dS)/(dt)) dt`
`int_(t = 0)^(t = 2) 3(2/3)((2t)/(3)) dt = 4/3 int_(0)^(2) t dt = 2.6 J`


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