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A body of mass 5 kg climb a height of 10 m by the force of 170 N . Its velocity at this heightwil be ………. |
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Answer» 15 m/s `= 170 xx10` ` = 1700 J ` gravitationalpotential energy U = MGH ` = 5 xx 10 xx10` = 500 J Now , kintic energy = `W - U ` ` :. 1/2 mv^(2) = 1700 - 500` ` :. 1/2 mv^(2) = 1200 J ` ` :. v = sqrt((2xx1200)/5) = sqrt((2400)/5)` ` :. v = sqrt(480)` = `21.90` ` :. v = 22` m/s (approximate) |
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