1.

A body of mass 5 kg climb a height of 10 m by the force of 170 N . Its velocity at this heightwil be ……….

Answer»

15 m/s
37 m/s
`9.8` m/s
22 m/s

Solution :Work done by force W = FH
`= 170 xx10`
` = 1700 J `
gravitationalpotential energy
U = MGH
` = 5 xx 10 xx10`
= 500 J
Now , kintic energy = `W - U `
` :. 1/2 mv^(2) = 1700 - 500`
` :. 1/2 mv^(2) = 1200 J `
` :. v = sqrt((2xx1200)/5) = sqrt((2400)/5)`
` :. v = sqrt(480)`
= `21.90`
` :. v = 22` m/s (approximate)


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